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Q86Section II (Mathematics)86 of 190

Non-vanishing Fredholm determinant forces the trivial solution alone

For the Fredholm integral equation u(t)=λ∫abk(t,s)u(s)dsu(t)=\lambda\int_a^bk(t,s)u(s)ds with separable kernel, Fredholm determinant D(λ)≠0D(\lambda)\neq0. Then the integral equation has:

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