Q70·Section II (Mathematics)·70 of 190Using Wilson's theorem to evaluate (50!)2 mod 101(50!)^2\bmod101(50!)2mod101Modulo the prime 101, the number (50!)2(50!)^2(50!)2 is congruent to: OptionsA−1-1−1B1C0D2Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q69All questionsQ71 →Keyboard: A–D answer · S solution · ←/→ previous/next