Q28·Section II (Mathematics)·28 of 180Residue extraction from the Laurent series of z4sin(1/z)z^4\sin(1/z)z4sin(1/z)∮∣z∣=1z4sin1z dz=\displaystyle\oint_{|z|=1}z^4\sin\frac1z\,dz=∮∣z∣=1z4sinz1dz= OptionsA12πi12\pi i12πiBπi60\dfrac{\pi i}{60}60πiC60πi60\pi i60πiDπi30\dfrac{\pi i}{30}30πiPick an option to check your answer.Show answerShow solution Report a problem with this question← Q27All questionsQ29 →Keyboard: A–D answer · S solution · ←/→ previous/next