Q50·Section II (Mathematics)·50 of 180Set difference of a half-open rectangle and a disk — when it becomes compactIf A={(x,y)/−1≤x<1,−1≤∣y∣≤1}A=\{(x,y)/-1\le x<1, -1\le|y|\le1\}A={(x,y)/−1≤x<1,−1≤∣y∣≤1} and B={(x,y)/(x−1)2+y2≤1/2}B=\{(x,y)/(x-1)^2+y^2\le1/2\}B={(x,y)/(x−1)2+y2≤1/2} then: OptionsAA\BA\backslash BA\B is compact in R2\mathbb{R}^2R2BB\AB\backslash AB\A is compact in R2\mathbb{R}^2R2CA∩BA\cap BA∩B is compact in R2\mathbb{R}^2R2DA∪BA\cup BA∪B is compact in R2\mathbb{R}^2R2Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q49All questionsQ51 →Keyboard: A–D answer · S solution · ←/→ previous/next