A Lagrangian of a particle of mass m is given by L=tfrac12mdot r^2-dfrac1r(1+dot r^2/c^2), c is a constant. Then:

Q96Section II (Mathematics)96 of 180

H is conserved even when it fails to equal the total energy

A Lagrangian of a particle of mass $m$ is given by $L=\tfrac12m\dot r^2-\dfrac1r\left(1+\dfrac{\dot r^2}{c^2}\right)$ , $c$ is a constant. Then:

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