Assume that Xsim B(n,p) for some nge1 and 0<p<1 and YsimPoisson(lambda) for some lambda0. Suppose E(X)=E(Y). Then:

Q125Section III (Statistics)125 of 180

Matching means — Binomial is always less dispersed than Poisson

Assume that $X\sim B(n,p)$ for some $n\ge1$ and $0<p<1$ and $Y\sim\operatorname{Poisson}(\lambda)$ for some $\lambda>0$ . Suppose $E(X)=E(Y)$ . Then:

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