Q16·Section I (General (compulsory))·16 of 180Eigenvalues of a polynomial in AAALet A=(100220114)A=\begin{pmatrix}1&0&0\\2&2&0\\1&1&4\end{pmatrix}A=121021004. Then the eigenvalues of the matrix A2−3A+2IA^{2}-3A+2IA2−3A+2I are: OptionsA0, 0, 60,\,0,\,60,0,6B−1, 1, 0-1,\,1,\,0−1,1,0C−2, 4, 18-2,\,4,\,18−2,4,18D0, 3, 120,\,3,\,120,3,12Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q15All questionsQ17 →Keyboard: A–D answer · S solution · ←/→ previous/next