Q57·Section II (Mathematics)·57 of 180Topology — the curve x2y2=1x^2y^2=1x2y2=1Let X={(x,y)∈R2:x2y2=1}X=\{(x,y)\in\mathbb{R}^2:x^2y^2=1\}X={(x,y)∈R2:x2y2=1}. Then: OptionsAX is compact and connectedBX is compact, but not connectedCX is connected, but not compactDX is neither compact nor connectedPick an option to check your answer.Show answerShow solution Report a problem with this question← Q56All questionsQ58 →Keyboard: A–D answer · S solution · ←/→ previous/next