Q3·Section I (General (compulsory))·3 of 841/(3+3i)=(1−i)/61/(3+3i)=(1-i)/61/(3+3i)=(1−i)/6If f(z)=z+1f(z)=z+1f(z)=z+1, then 1f(2+3i)\dfrac1{f(2+3i)}f(2+3i)1 is: OptionsA1+i6\dfrac{1+i}661+iB1−i6\dfrac{1-i}661−iC2−3i13\dfrac{2-3i}{13}132−3iD3+3i3+3i3+3iPick an option to check your answer.Show answerShow solution Report a problem with this question← Q2All questionsQ4 →Keyboard: A–D answer · S solution · ←/→ previous/next