Q4·Section I (General (compulsory))·4 of 84Only the 1/z1/z1/z term contributes: residue 1∫∣z∣=2(z+1) dzz\displaystyle\int_{|z|=2}\frac{(z+1)\,dz}z∫∣z∣=2z(z+1)dz is: OptionsA−2πi-2\pi i−2πiB2π2\pi2πC2πi2\pi i2πiD4πi4\pi i4πiPick an option to check your answer.Show answerShow solution Report a problem with this question← Q3All questionsQ5 →Keyboard: A–D answer · S solution · ←/→ previous/next