Q57·Section II (Mathematics)·57 of 145Twisted cubic at the origin: ∣α′×α"∣/∣α′∣3=2|\alpha'\times\alpha"|/|\alpha'|^3=2∣α′×α"∣/∣α′∣3=2Let α:(−1,1)→R3\alpha:(-1,1)\to\mathbb{R}^3α:(−1,1)→R3 be defined by α(t)=(t,t2,t3)\alpha(t)=(t,t^2,t^3)α(t)=(t,t2,t3). Then the curvature k(t)k(t)k(t) at t=0t=0t=0 is: OptionsA3B2\sqrt22C2D1Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q56All questionsQ58 →Keyboard: A–D answer · S solution · ←/→ previous/next