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Q57Section II (Mathematics)57 of 145

Twisted cubic at the origin: ∣α′×α"∣/∣α′∣3=2|\alpha'\times\alpha"|/|\alpha'|^3=2

Let α:(−1,1)→R3\alpha:(-1,1)\to\mathbb{R}^3 be defined by α(t)=(t,t2,t3)\alpha(t)=(t,t^2,t^3). Then the curvature k(t)k(t) at t=0t=0 is:

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