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Q58Section II (Mathematics)58 of 145

Helicoid: E=v2+a2E=v^2+a^2, F=0F=0, G=1G=1

For 0<u<2π0<u<2\pi, −∞<v<∞-\infty<v<\infty, the helicoid is xˉ(u,v)=(vcos⁡u,vsin⁡u,au)\bar x(u,v)=(v\cos u, v\sin u, au). Then the coefficients E, F, G in the first fundamental form of the helicoid are:

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