Q105·Section III (Statistics)·105 of 190Markov's inequality on the third absolute momentLet X be a random variable with E[∣X∣3]=3E[|X|^3]=3E[∣X∣3]=3. Then: OptionsAP[∣X∣≤2]≤3/8P[|X|\le2]\le3/8P[∣X∣≤2]≤3/8BP[∣X∣≤2]≤3/5P[|X|\le2]\le3/5P[∣X∣≤2]≤3/5COne cannot say anything about P[∣X∣≤2]P[|X|\le2]P[∣X∣≤2] from the given informationDP[∣X∣≤2]≥5/8P[|X|\le2]\ge5/8P[∣X∣≤2]≥5/8Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q104All questionsQ106 →Keyboard: A–D answer · S solution · ←/→ previous/next