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Q106Section III (Statistics)106 of 190

Reading a probability off a joint table

Let the joint distribution of (X,Y)(X,Y) be given by the table below (Y in {0,1}\{0,1\} down the side, X in {0,1,2,3}\{0,1,2,3\} across the top): P(0,0)=110,P(1,0)=120,P(2,0)=120,P(3,0)=120;P(0,1)=320,P(1,1)=15,P(2,1)=320,P(3,1)=520P(0,0)=\frac1{10},P(1,0)=\frac1{20},P(2,0)=\frac1{20}, P(3,0)=\frac1{20}; P(0,1)=\frac3{20},P(1,1)=\frac15, P(2,1)=\frac3{20},P(3,1)=\frac5{20}. Then P[X≤1]P[X\le1] is:

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