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Q140Section III (Statistics)140 of 190

Decomposing a mixed distribution function into its discrete and continuous parts

Suppose a distribution function F:R→[0,1]F:\mathbb{R}\to[0,1] is as follows: F(x)=0F(x)=0 for x<0x<0; 1/41/4 for 0≤x<10\le x<1; 1/21/2 for 1≤x<21\le x<2; 1/2+(x−2)/21/2+(x-2)/2 for 2≤x<32\le x<3; 11 for x≥3x\ge3. Then F(x)=l1F1(x)+l2F2(x)F(x)=l_1F_1(x)+l_2F_2(x) where:

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